Question

A soma dos 6 termos da PG com a1=5 e q=2
Sn= a1. (1-q n)
1-q

Sn=a1. (q-1 n-)
q-1

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ a1 = 5 \\ q = 2 \\ n = 6 \\ \\ = = = = = = = = = = = = = = = \\ \\ > \: soma \: dos \: termos \: da \: pg \\ \\ sn = \frac{a1(q {}^{n} - 1) }{q - 1} \\ \\ sn = \frac{5(2 {}^{6} - 1)}{2 - 1} \\ \\ sn = \frac{5(64 - 1)}{1} \\ \\ sn = \frac{5 \times 63}{1} \\ \\ sn = 315 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$