Question

A soma do coeficiente angular com o coeficiente linear da reta que passa pelos pontos A(0,
4) e B(-3, 2)
O 14/3
2
06
O 10/3

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo-a-passo:

$\mathsf{\dfrac{\Delta_Y}{\Delta_X} = \dfrac{y_B - y_A}{x_B - x_A} = \dfrac{2 - 4}{-3-0} = \dfrac{-2}{-3} = \dfrac{2}{3}}$

$\mathsf{y - y_0 = m(x - x_0)}$

$\mathsf{y - 4 = \dfrac{2}{3}(x - 0)}$

$\mathsf{3y - 12 = 2x}$

$\mathsf{3y = 2x + 12}$

$\mathsf{y = \dfrac{2x}{3} + \dfrac{12}{3}}$

$\mathsf{y = \dfrac{2x}{3} + 4}$

$\mathsf{y = ax + b}$

$\mathsf{a + b = \dfrac{2}{3} + 4}$

$\mathsf{a + b = \dfrac{2+ 12}{3}}$

$\boxed{\boxed{\mathsf{a + b = \dfrac{14}{3}}}}$