Matemática, perguntado por evellynsantos6969, 5 meses atrás

A soma de dois números de 100 e o maior deles é igual ao dobro do menor mais 4

Soluções para a tarefa

Respondido por CyberKirito
1

\large\boxed{\begin{array}{l}\underline{\rm Resoluc_{\!\!,}\tilde ao\,por\,sistema\,de\,equac_{\!\!,}\tilde oes}\\\begin{cases}\sf x+y=100\\\sf y=x+4\end{cases}\\\sf x+(x+4)=100\\\sf x+x+4=100\\\sf 2x+4=100\\\sf 2x=100-4\\\sf 2x=96\\\sf x=\dfrac{96}{2}\\\\\sf x=48\\\sf y=x+4\\\sf y=48+4\\\sf y=52\\\rm os\,n\acute umeros\,s\tilde ao\,48\,e\,52.\end{array}}

\large\boxed{\begin{array}{l}\underline{\rm Resoluc_{\!\!,}\tilde ao\,por\,equac_{\!\!,}\tilde ao\,de\,1^o\,grau}\\\sf n\acute umero\longrightarrow x\\\sf outro\,n\acute umero\longrightarrow x+4\\\sf equac_{\!\!,}\tilde ao: x+(x+4)=100.\\\underline{\rm soluc_{\!\!,}\tilde ao\!:}\\\sf x+(x+4)=100\\\sf x+x+4=100\\\sf 2x=100-4\\\sf 2x=96\\\sf x=\dfrac{96}{2}\\\\\sf x=48\\\sf o\,outro\,n\acute umero\,\acute e~48+4=52.\end{array}}

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