Question

A soma das raízes da equação senx = √3cosx no intervalo [0,2π] é:

a)π
b)5π/3
c)2π/3
d)7π/3
e)π/2

Answer 1

Boa tarde

sen(x) = √3cosx

tg(x) = sen(x)/cos(x) = √3

x = π/3 
x = π + π/3 = 4π/3

soma
π/3 + 4π/3 = 5π/3 (B)