Question

A solução dos sistemas

X+Y+Z=30
X/7 = Y/3 = Z/5 é

a) x = 6, y = 14 e z = 10 d) x = 4, y = 5 e z = 21
b) x = 14, y = 6 e z = 10 e) x = 5, y = 4 e z = 21
c) x = 8, y = 5 e z =

Answer 1

x/7 = y/3 = z/5

x + y + z = 30
7 + 3 + 5 = 15
30/15 = x/7
15 . x = 30 . 7
x = 210/15
x = 14
30/15 = y /3
15 . y = 30 . 3
y = 90/15
y = 6

30/15 = z / 5
15 .z = 30 . 5
z = 150/15
z = 10
Resposta letra b