Question

A solução do problema de valor inicial
y' + 1x = 2: y(0) = 3 é​

Answer 1

y' = -x + 2

y = $\int\limits {-x+2} \, dx =-\frac{x^2}{2} +2x+C$

y(0) = 3

3 = $-\frac{0^2}{2} +2(0)+C$

C = 3