Question

A solucao da equacao expotencial a sequir (7/8)=(64/49)^3x-1 A-1/6 B1/6 C--1/3 D1/3 E-1/2

Answer 1

$\frac{7}{8}=\left(\frac{64}{49}\right)^{3x-1}\\\\\frac{7}{8}=\left(\frac{8^2}{7^2}\right)^{3x-1}\\\\\frac{7}{8}=\left(\frac{8}{7}\right)^{2^{3x-1}}\\\\\left(\frac{8}{7}\right)^{-1}=\left(\frac{8}{7}\right)^{2.(3x-1)}\\\\-1=2.(3x-1)\\\\-1=6x-2\\\\6x=1\\\\x=\frac{1}{6}$