a solução da equação 1/3 x - 1/2 = 0,2x + 0,1333.. é um numero racional x. o valor numérico desse número rcional x é.
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Olá, Alexandra.
![\frac{1}{3}x - \frac{1}{2} = 0,2x + 0,1333..= \frac{1}{5}x+\frac{1,333...}{10}=\frac x 5+\frac{1+0,333...}{10} = \frac x 5+\frac1{10}+\frac{0,333...}{10} =\\\\=\frac x 5+\frac1{10}+\frac39\cdot\frac1{10}=\frac x 5+\frac1{10}+\frac3{90} \Rightarrow
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\frac{x}{3}-\frac x 5 =\frac1{10}+\frac3{90}+\frac12 \Rightarrow\frac{5x-3x}{15}= \frac{9+3+45}{90}\Rightarrow \frac{2x}{15}=\frac{57}{90}
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x=\frac{57}{90}\cdot\frac{15}{2}=\frac{57}{6}\cdot\frac{1}{2}=\frac{19}{2}\cdot\frac{1}{2} \frac{1}{3}x - \frac{1}{2} = 0,2x + 0,1333..= \frac{1}{5}x+\frac{1,333...}{10}=\frac x 5+\frac{1+0,333...}{10} = \frac x 5+\frac1{10}+\frac{0,333...}{10} =\\\\=\frac x 5+\frac1{10}+\frac39\cdot\frac1{10}=\frac x 5+\frac1{10}+\frac3{90} \Rightarrow
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\frac{x}{3}-\frac x 5 =\frac1{10}+\frac3{90}+\frac12 \Rightarrow\frac{5x-3x}{15}= \frac{9+3+45}{90}\Rightarrow \frac{2x}{15}=\frac{57}{90}
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x=\frac{57}{90}\cdot\frac{15}{2}=\frac{57}{6}\cdot\frac{1}{2}=\frac{19}{2}\cdot\frac{1}{2}](https://tex.z-dn.net/?f=++%5Cfrac%7B1%7D%7B3%7Dx+-++%5Cfrac%7B1%7D%7B2%7D+%3D+0%2C2x+%2B+0%2C1333..%3D+%5Cfrac%7B1%7D%7B5%7Dx%2B%5Cfrac%7B1%2C333...%7D%7B10%7D%3D%5Cfrac+x+5%2B%5Cfrac%7B1%2B0%2C333...%7D%7B10%7D+%3D+%5Cfrac+x+5%2B%5Cfrac1%7B10%7D%2B%5Cfrac%7B0%2C333...%7D%7B10%7D+%3D%5C%5C%5C%5C%3D%5Cfrac+x+5%2B%5Cfrac1%7B10%7D%2B%5Cfrac39%5Ccdot%5Cfrac1%7B10%7D%3D%5Cfrac+x+5%2B%5Cfrac1%7B10%7D%2B%5Cfrac3%7B90%7D+%5CRightarrow%0A%5C%5C%5C%5C%0A%5Cfrac%7Bx%7D%7B3%7D-%5Cfrac+x+5+%3D%5Cfrac1%7B10%7D%2B%5Cfrac3%7B90%7D%2B%5Cfrac12+%5CRightarrow%5Cfrac%7B5x-3x%7D%7B15%7D%3D+%5Cfrac%7B9%2B3%2B45%7D%7B90%7D%5CRightarrow+%5Cfrac%7B2x%7D%7B15%7D%3D%5Cfrac%7B57%7D%7B90%7D%0A%5C%5C%5C%5C%0Ax%3D%5Cfrac%7B57%7D%7B90%7D%5Ccdot%5Cfrac%7B15%7D%7B2%7D%3D%5Cfrac%7B57%7D%7B6%7D%5Ccdot%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B19%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B2%7D)
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