Question

A sentença $3^{7}$÷$3^{2}$.$2^{5}$-$3^{-1}$.$9^{3}$+$( \sqrt{3}) ^{6}$.2.$3^{2}$ equivale a:

a) $6^{5}$+$3^{5}$
b) $2^{6}$+$3^{15}$
c) $2^{6}$+$3^{9}$-$9^{3}$
d) $2^{5}$.$3^{25}$

Favor explicar o raciocínio.

Answer 1

3^7.2^5 - 3^-1.9^3 + (V3^6 .2.3^2 
3^2

[3^(7-2).2^5] - 3^-1.(3^2)^3 + 3^3.3^2.2

[3^(7-2).2^5] - 3^-1.3^6 + 3^(3+2).2

[3^5.2^5] - 3^(-1+6) + 3^(3+2).2

[3^5.2^5] - 3^5 + 2.3^5  

3^5.2^5 + 3^5

(3.2)^5 + 3^5

6^5 + 3^5  

Letra A