Question

A sentenç aij = x.i −j define a matriz (1 0 3 2 ). Sendo assim, x vale:

Answer 1

$\left[\begin{array}{cccc}1&0&3&2\end{array}\right]$

Sendo:
$\left[\begin{array}{cccc} a_{11} & a_{12} & a_{13} & a_{14} \end{array}\right]$

Temos:
$a_{ij} = x*i-j$

Resolução:
$a_{11} = x*1-1$ → $1 = x-1$ → $x = 1+1$ → $\boxed{x = 2}$

$a_{12} = x*1-2$ → $0 = x-2$ → $\boxed{x = 2}$ 

$a_{13} = x*1-3$ → $3 = x-3$ → $x = 3+3$ → $\boxed{x = 6}$

$a_{14} = x*1-4$ → $2 = x-4$ → $x = 4+2$ → $\boxed{x = 6}$