Question

A raiz quadrada de (10^20 + 1)^2 - 10^40 é igual a :

A)1
B)2
C)1 + 10^10 V2
D)(10^10 + 1)V2
E)Raiz Quadrada de 2.10^20 +1

Answer 1

$\sqrt{(10^2^0+1)^2} -10^4^0$
$\sqrt{(10^2^0)^2} +2.10^2^0.1+1^2-10^4^0$
$\sqrt{10^4^02.10^2^0+1-10^4^0}$
$\sqrt{2.10^2^0+1}$
Letra E