Question

A raiz da equação log [log (x+1)]= 0??

Answer 1

$\mathrm{\ell og}\left[\mathrm{\ell og}(x+1) \right ]=0\\ \\ \mathrm{\ell og}\left[\mathrm{\ell og}(x+1) \right ]=\mathrm{\ell og\,}1$


Igualando os logaritmandos, temos

$\mathrm{\ell og}(x+1)=1\\ \\ \mathrm{\ell og}(x+1)=\mathrm{\ell og\,}10\\ \\ \\ x+1=10\\ \\ x=10-1\\ \\ x=9$