Question

A questao 7 pfv, sobre equaçao

Answer 1

$1-\dfrac{3(x+2)}{4}=\dfrac{3-x}{2}-\dfrac{7}{8}$

Multiplique os dois lados por 8:

$8\cdot\left(1-\dfrac{3(x+2)}{4}\right)=8\cdot\left(\dfrac{3-x}{2}-\dfrac{7}{8}\right)$

$8-\dfrac{24(x+2)}{4}=\dfrac{8(3-x)}{2}-\dfrac{8\cdot7}{8}$

$8-6(x+2)=4(3-x)-7$

$8-6x-12=12-4x-7$

$-6x+4x=12+12-8-7$

$-2x=9$

$x=\dfrac{9}{-2}=-4,5$

Entre -5 e -4.

Letra A