Question

a menor raiz de equacao x2+9×+8=0,e:

Answer 1

x²+9x+8=0 onde a=1; b=9; c=8
Δ=b²-4.a.c
Δ=9²-4.1.8
Δ=81-32
Δ=49
x=$\frac{-b \frac{+}{-} \sqrt{Δ} }{2.a}$
x=$\frac{-9 \frac{+}{-} \sqrt{49} }{2.1}$
x=$\frac{-9 \frac{+}{-}7 }{2}$
x'=$\frac{-9+7}{2}$
x'=$\frac{-2}{2}$
x'=-1
x"=$\frac{-9-7}{2}$
x"=$\frac{-16}{2}$
x"=-8
S={-1,-8}