Question

a)log2 (256/32)

b)log2 32+log3 27-log5⁵
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Answer 1

Resposta:

$a) log_{2}( \frac{256}{32} )$

$log_{2}256 - log_{2}32 = 8 - 5 = 3$

$b) log_{2}32 + log_{3}27 - log {5}^{5}$ =

$5 + 3 - 5 log5 = 8 - 5 log5$

Espero ter te ajudado.