Question

A) Log 2 base 16
B) log 1000 base 100
C) log 49 base 7
D) log 7 base 49

Answer 1

A) Log 2  = x ==> 16^x = 2^1 ==> (2^4)^x = 2^1 => 2x = 1 => x = 1/4 
         16 
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B) log 1000  = 100^x = 1000 ==> (10^2)^x = 10^3 => 2x = 3 ==> x = 3/2
         100
C) log 49 => 7^x = 7^2 ==> x = 2 
         7
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D) log 7  = x ==> 49^x = 7^1 ==> (7^2)^x = 7^1 => 2x = 1 => x = 1/2 
         49