Question

A HIPOTENUZA DO TRIANGULO ABC MEDE 10 CM E SEN B=3|5 DETERMINE A MEDIDA DE AB

Answer 1

$sen \alpha = \frac{C.o}{H}$

$Senb= \frac{x}{10}$

$\frac{3}{5} = \frac{x}{10}$

$3.10=5x$

$30=5x$

$\frac{30}{5}=x$

$x=6cm$

O lado Ab tem 6cm