Question

A fração é igual a:​

Answer 1

Explicação passo-a-passo:

$\sf E=\dfrac{2^{98}+4^{50}-8^{34}}{2^{99}-32^{20}+2^{101}}$

$\sf E=\dfrac{2^{98}+(2^2)^{50}-(2^3)^{34}}{2^{99}-(2^5)^{20}+2^{101}}$

$\sf E=\dfrac{2^{98}+2^{2\cdot50}-2^{3\cdot34}}{2^{99}-2^{5\cdot20}+2^{101}}$

$\sf E=\dfrac{2^{98}+2^{100}-2^{102}}{2^{99}-2^{100}+2^{101}}$

$\sf E=\dfrac{2^{98}+2^{98}\cdot2^2-2^{98}\cdot2^4}{2^{98}\cdot2-2^{98}\cdot2^2+2^{98}\cdot2^3}$

$\sf E=\dfrac{2^{98}\cdot(1+2^2-2^4)}{2^{98}\cdot(2-2^2+2^3)}$

$\sf E=\dfrac{1+2^2-2^4}{2-2^2+2^3}$

$\sf E=\dfrac{1+4-16}{2-4+8}$

$\sf \red{E=\dfrac{-11}{6}}$

Letra B