Question

A distancia entre os pontos M(4,-5) e N(-1,7) do plano x0y vale:

a)14
b)13
c)12
d)9
e)8

Answer 1

Utilize a fórmula da Geometria Analíotica:

$d=\sqrt{(x_N-x_M)^2+(y_N-y_M)^2}\\ \\ d=\sqrt{(-1-4)^2+(7-(-5))^2}=\sqrt{(-5)^2+12^2}\\ \\ d=\sqrt{25+144}=\sqrt{169}=13$

Answer 2

$M(4,-5) \\ N(-1,7) \\ \\ \\ d_{M,N} = \sqrt{ ( x_{b} - x_{a} )^{2} + ( y_{a} - y_{b} )^{2} } \\ \\ \\ d_{M,N} = \sqrt{ (-1-4)^{2} + (7-(-5))^{2} } \\ \\ d_{M,N} = \sqrt{( -5)^{2}+( 7+5)^{2} } \\ \\ d_{M,N} = \sqrt{( -5)^{2}+( 12)^{2} } \\ \\ d_{M,N} = \sqrt{25+144} \\ \\ d_{M,N} = \sqrt{169} \\ \\ d_{M,N} = 13$



Resposta Correta: LETRA B)