Question

a área de um triângulo trapézio com menor de 5cm, base maior 12cm e autura de 10cm?
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Answer 1

$\large\boxed{\begin{array}{l}\underline{\rm \acute Area~do~trap\acute ezio}\\\sf A=\dfrac{(B+b)\cdot h}{2}\\\\\tt dados\begin{cases}\sf b=5~cm\\\sf B=12~cm\\\sf h=10~cm\end{cases}\\\sf A=\dfrac{(12+5)\cdot \diagdown\!\!\!\!\!10^5}{\diagdown\!\!\!\!\!2}\\\sf A=17\cdot5\\\sf A=85~cm^2\end{array}}$