Question

A=(aij) 2x3, tal que aij= 2i²-2j²

Answer 1

É para montar a matriz? Ela ficaria assim:

$a_{11}=2.1^2-2.1^2=2-2=0$

$a_{12}=2.1^2-2.2^2=2-2.4=2-8=-6$

$a_{13}=2.1^2-2.3^2=2-2.9=2-18=-16$

$a_{21}=2.2^2-2.1^2=2.4-2=8-2=6$

$a_{22}=2.2^2-2.2^2=0$

$a_{23}=2.2^2-2.3^2=2.4-2.9=8-18=-10$

$A=\left[\begin{array}{ccc}0&-6&-16\\6&0&-10\end{array}\right]$