Question

a, (-5a²-8x+9)+(8x²+8x+18)


b, (-6x³-4x²+8x-1)+(5x²+5x+16)

Answer 1

Resposta:

$a)( - 5a {}^{2} - 8x + 9) + (8x {}^{2} + 8x + 18) = \\ ( - 5a {}^{2} - 8x + 9) + (8x {}^{2} + 8x + 18) \\ - 5a {}^{2} - 8x + 9 + (8x {}^{2} + 8x + 18 \\ ( - 5a {}^{2} - 8x + 9) + (8x {}^{2} + 8x + 18) \\ - 5a {}^{2} - 8x + 9 + 8x {}^{2} + 8x + 18 \\ - 5a {}^{2} + 9 + 8x {}^{2} + 18 \\ - 5a {}^{2} - 8x + 9 + 8x {}^{2} + 8x + 18 \\ - 5a {}^{2} + 27 + 8x {}^{2} \\ resposta \\ - 5a {}^{2} + 27 + 8x {}^{2} \\ \\ b)( - 6x {}^{3} - 4x {}^{2} + 8x - 1) + (5x {}^{2} + 5x + 16) = \\ ( - 6x {}^{3} - 4x {}^{2} + 8x - 1) + (5x {}^{2} + 5x + 16) \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + (5x {}^{2} +5x + 16) \\ ( - 6x {}^{3} - 4x {}^{2} + 8x - 1) + (5x {}^{2} + 5x + 16) \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x + 16 \\ - 4x {}^{2} + 5x {}^{2} \\ ( - 4 + 5)x {}^{2} \\1x {}^{2} \\ x {}^{2} \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x +16 \\ - 6x {}^{3} + x {}^{2} + 8x - 1 + 5x {}^{2} + 5x + 16 \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x + 16 \\ 8x + 5x \\ (8 + 5)x \\ 13x \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x + 16 \\ - 6x {}^{3} + x {}^{2} + 13x - 1 + 16 \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x + 16 \\ - 1 + 16 \\ + (16 - 1) \\ 15 \\ - 6x {}^{3} - 4x {}^{2} + 8x - 1 + 5x {}^{2} + 5x \\ + 16 \\ - 6x {}^{3} + x {}^{2} + 13x + 15 \\ resposta \\ - 6x {}^{3} + x {}^{2} + 13x + 15$