Question

A) (4x+1)²= (3x-7)²

B)-x²+4x+12=0

C)x² +x-12=0

Answer 1

(4x)² +2(4x( +1) +1²=(3x)² -2(3x(-7) +(-7)²=

8x² +5x +1 = 9x² +42x -49

8X² -9x² +5x -42X +1+49=0

-X² -37x +50

Δ=(-37)²-4(-1).50)

Δ=1369 +200

Δ=1569

B) -x² +4x+12=0

Δ=4²-4(-1)12)

Δ=16+48

Δ=64

X= -4+-8/2.-1

X= - 4+8/-2

X,=4/2=

X,=2

X= -4-8/-2

X=-12/-2

X,,=6

C)x²+x-12=0

Δ=1²_4(1(-12)

Δ= 1+48

Δ=49

X=-1+-7/2

X,=1+7/2

X,=8/2

X,=4

X,,=1-7/2

X,,=-6/2

X,,= -3