Question

a)3(x-1)=5-2x

b)2+2x=6(x-5)

c(5x-2(x-1)=7-4x

d)2(x+1)=3(x+2)

e)3x+2(x+1)=3x-2

f)6x-3(5-2x)=0

g)2(x+3)=5(x+3)+1

h)4(-2x+5)=-5(x+3)+1

i)3(4x-7)-(4x-9)=7x-11

j)-2(x-5)-1=3x+6+1-x)​

Answer 1

Resposta:

a)3(x-1)=5-2x

3x - 3 = 5 - 2x

3x + 2x - 3 = 5

5x = 5 + 3

5x = 8

x= $\frac{8}{5}$

b)2+2x=6(x-5)

2 + 2x = 6x - 30

2x = 6x - 2 - 30

2x - 6x = -2 - 30

- 4x = - 32 . (-1)

4x = 32

x = $\frac{32}{4}$

x = 8

c(5x-2(x-1)=7-4x

5x - 2x + 2 = 7 - 4x

3x + 2 = 7 - 4x

3x + 4x + 2 = 7

7x = 7 -2

7x = 5

x= $\frac{5}{7}$

d)2(x+1)=3(x+2)

2x+ 2= 3x + 6

2x - 3x + 2 = 6

-x = 6 - 2

-x = 4 . (-1)

x = -4

e)3x+2(x+1)=3x-2

3x + 2x + 2 = 3x - 2

5x + 2 = 3x - 2

5x - 3x = - 2 -2

2x = -4

x = -$\frac{4}{2}$

x = -2

f)6x-3(5-2x)=0

6x - 15 + 6x = 0

12x = + 15

x = $\frac{15}{12}$ : 3

x = $\frac{5}{4}$

g)2(x+3)=5(x+3)+1

2x + 6 = 5x + 15 + 1

2x + 6 = 5x + 16

2x - 5x + 6 = 16

-3x = 16 - 6

-3x = 10

x = -$\frac{10}{3}$

h)4(-2x+5)=-5(x+3)+1

-8x + 20 = -5x - 15 + 1

-8x + 20 + 5x = - 14

- 3x = -14 - 20

- 3x = - 34 . (-1)

3x = 34

x = $\frac{34}{3}$

i)3(4x-7)-(4x-9)=7x-11

12x - 21 - 4x + 9 = 7x - 11

8x - 12 = 7x - 11

8x - 7x = -11 + 12

x = 1

j)-2(x-5)-1=3x+6+1-x)​

-2x + 10 - 1 = 3x + 7 - x

-2x + 9 = 2x + 7

-2x -2x +9 =7

-4x = 7 -9

-4x = -2 . (-1)

4x = 2

x = $\frac{2}{4}$ : 2

x = $\frac{1}{2}$

Explicação passo-a-passo: