Question

a) (2x²-9x+2)+(3x²+7x-1)=

b) (5x²-4x+7)-(3x²+7x-1)=

c) (x+5).(x+2)=

d) (12x²-8x)÷(2x)=

Answer 1

$a) \: (2 {x}^{2} - 9x + 2) + (3 {x}^{2} + 7x - 1) \\ 5 {x}^{2} - 2x + 1$

$b) \: (5 {x}^{2} - 4x + 7) - (3 {x}^{2} + 7x - 1) \\ 5 {x}^{2} - 4x + 7 - 3 {x}^{2} - 7x + 1 \\ 2 {x}^{2} - 11x + 8$
$c) \: (x + 5) \times (x + 2) \\ {x}^{2} + 2x + 5x + 10 \\ {x}^{2} + 7x + 10$
$d) \: (12 {x}^{2} - 8) \div (2x) \\ \frac{12 {x}^{2} - 8 }{2} \times x \\ \frac{2(6 {x}^{2} - 4)}{2} \times x \\ (6 {x}^{2} - 4) \times x \\ 6 {x}^{3} - 4x$