Question

A) -√100 + ³√27 - 2

B) -(-7) +-√1 /2.6

Answer 1

$\sqrt{100} = \sqrt{ 10^{2} } = 10^{ \frac{2}{2} } =10$
$\sqrt[3]{27} = \sqrt[3]{ 3^{3} } = 3^{ \frac{3}{3} } =3$
A)$- \sqrt{100} + \sqrt[3]{27} - 2 = -10+3-2=-9$
B)$-(-7) +(- \sqrt{ \frac{1}{2,6} } ) = 8 - \frac{1}{ \sqrt{2,6} }= 8- \frac{1}{1,61} =8-0,62=7,38$