Question

A -1/5 elevado a 3
B -3/10 elevado a 2
C 1/3 elevado a 5
D -2/5 elevado a -3
E -7 elevado a -2

Answer 1

Resposta:

$a)\\ ( \frac{ - 1}{5} ) {}^{3} = ( - \frac{1}{5}) \times ( - \frac{1}{5} ) - \times \: ( - \frac{1}{5} ) \\ = \frac {1}{25} \times (- \frac{1}{5 }) \\ = - \frac{1}{125}$

$( - \frac{3}{10} ) ^{2} = - \frac{3}{10} \times ( - \frac{3}{10} ) \\ = \frac{9}{100}$

$( \frac{1}{3} ) {}^{5} = \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \\ = \frac{1}{9} \times \frac{1}{9} \times \frac{1}{3} \\ = \frac{1}{81} \times \frac{1}{3} \\ = \frac{1}{243}$

$( - \frac{2}{5} ) {}^{ - 3} = \frac{1}{ ( - \frac{2}{5}) {}^{3} } \\ = 1 \times ( - \frac{5}{2} ) ^{3} \\ = \frac{ - 125}{8}$

$( - \frac{2}{5} ) {}^{ - 3} = \frac{1}{ ( - \frac{2}{5}) {}^{3} } \\ = 1 \times ( - \frac{5}{2} ) ^{3} \\ = \frac{ - 125}{8} \\ - 7 {}^{ - 2} = ( - \frac{1}{7} ) {}^{2} \\ = \frac{1}{49}$