Question

9y²-12y+4=0 ! me ajudem a encontrar a raiz

Answer 1

9y^2-12y+4=0!
9y^2-12y+4=1
9y^2-12y+4-1
9y^2-12y+3=0
delta=b^2-4ac
delta=(-12)^2-4.9.3
delta=144-108
delta=36
y=-b-/+ raiz de delta/2a
y=-(-12)-6/2.9
y=12-6/18
y=6/18 (÷6)
y=1/3
y=-(-12)+6/2.9
y=12+6/18
y=18/18
y=1
S={1/3, 1}

Answer 2

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf 9y^2-12y+4=0$

$\sf y=\dfrac{-(-12)\pm\sqrt{(-12)^2-4\cdot9\cdot4} }{2\cdot9}$

$\sf y=\dfrac{-(-12)\pm\sqrt{144-4\cdot9\cdot4} }{2\cdot9}$

$\sf y=\dfrac{-(-12)\pm\sqrt{144-36\cdot4} }{2\cdot9}$

$\sf y=\dfrac{-(-12)\pm\sqrt{144-144} }{2\cdot9}$

$\sf y=\dfrac{-(-12)\pm\sqrt{0} }{2\cdot9}$

$\sf y=-\dfrac{-12 }{2\cdot9}$

$\sf y=\dfrac{12 }{2\cdot9}$

$\sf y=\dfrac{12}{18}$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{y=\frac{2}{3}\approx0,666666667 }}}}\ \checkmark$← RESPOSTA.

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