Question

9x2+6x+1=0 como resolver?

Answer 1

9x²+6x+1=0
a:9 b:6 c:1
∆=b²-4.a.c
∆=6²-4.9.1
∆=36-36
∆=0

-b+-√∆/2.a
-6+-0/18

x=-6/18
x=-1/3

S= {(-1/3)}