Question

9x²-24x+16=0 calcule o valor do delta

Answer 1

Δ = b² - 4ac

Δ = 24² - 4*9*16

Δ = 576 - 576

Δ = 0

x = --24 +/- √0 / 2*9

x = 24 +/- 0 / 18

x' e x'' = 24 +/- 0 = 24

Espero ter ajudado :)

Answer 2

9x² - 24x + 16:0 A: 9, B: - 24, C: 16

Δ: b²- 4ac

Δ: ( -24)²- 4.9.16: 0

Δ: 576 - 576: 0

Δ: 0