Question

[9 quartos+(1 terço- sete sextos)+2]=

Answer 1

$[\dfrac94+(\dfrac13-\dfrac76)+2]\\\\\ [\dfrac{27}{12}+(\dfrac{4}{12}-\dfrac{14}{12})+\dfrac{24}{12}]\\\\\ [\dfrac{27}{12}+(-\dfrac{10}{12})+\dfrac{24}{12}]\\\\\ [\dfrac{27}{12}-\dfrac{10}{12}+\dfrac{24}{12}]\\\\\ [\dfrac{27-10+24}{12}]=\dfrac{41}{12}$