Question

9) Numa das região quentes o termômetro indica 42°C. Qual será o valor dessa temperatura
na escala Fahrenheit?

Answer 1

$\boxed{\dfrac{T_C}{5}=\dfrac{T_F-32}{9}=\dfrac{T_K-273}{5}}$

$T_F-32=\dfrac{9T_C}{5}\ \therefore\ \boxed{T_F=1.8T_C+32}$

$T_C=42\ºC\ \to\ T_F=1.8(42)+32\ \therefore$

$\boxed{T_F=107.6\ºF}$