Question

9)_
Determine quantos termos tem a PG (16,18...1458)

Answer 1

$q= \frac{18}{16}= \frac{9}{8} \\ a_{n}=a_{1}. q^{n-1} \\ \\ 1458=16.( \frac{9}{8}) ^{n-1} \\ \\ \frac{1458}{16}= ( \frac{9}{8}) ^{n-1} \\ \\ \frac{729}{8}= ( \frac{9}{8}) ^{n-1} \\ \\ ( \frac{9}{2})^{3}= ( \frac{9}{8}) ^{n-1}$