Question

9/8+8/9 x [1-(3/4+1/2)]³= 
conta 

Answer 1

$\frac{9}{8}+\frac{8}{9} . [1-(\frac{3}{4}+\frac{1}{2})]^3= \\ \\ \frac{9}{8}+\frac{8}{9}.[1-\frac{5}{4}]^3= \\ \\ \frac{9}{8}+\frac{8}{9}.[-\frac{1}{4}]^3= \\ \\ \frac{9}{8}+\frac{8}{9}.(-\frac{1}{64})= \\ \\ \frac{9}{8}-\frac{8}{576}=\frac{648-8}{576}=\frac{640}{576}=\frac{10}{9}$