Question

88) na equaçao y=3 log 2 (x-1),se y=1/3, o valor de x será​

Answer 1

Resposta:

y=3^[log₂ (x-1)]        ...y=1/3=3⁻¹

3⁻¹ = 3^[log₂ (x-1)]

-1 =  log₂ (x-1)

Observe ******logₙ a  = x   ==>   a=nˣ

2⁻¹ =x-1

x=1/2+1

x=1/2+2/2 =3/2

Letra A