Question

8.(n+3)! / (n+1)! =1​

Answer 1

8.(n+3)!/(n+1)!=1

8.(n+3)(n+2)(n+1)!/(n+1)!=1

8(n+3)(n+2)=1

8.(n+3)(n+2)=1

8(n²+5n+6)=1

8n²+40n+48=1

8n²+40n+47=0

n=-b+-√b²-4ac/2a

n=-40+-√(40)²-4(8)(47)/16

n=-40+-√96/16

n=-40+√96/16 ou n=-40-√96/16