Question

(7v3-5v48+2v192):3v3

Answer 1

$\frac{7 \sqrt{3} - 5 \sqrt{48} + 2 \sqrt{192} }{3 \sqrt{3} } = \frac{7 \sqrt{3} - 5.4 \sqrt{3}+2.8 \sqrt{3} }{3 \sqrt{3} }= \frac{7 \sqrt{3}-20 \sqrt{3}+16 \sqrt{3} }{3 \sqrt{3} }= \frac{23 \sqrt{3}-20 \sqrt{3} }{3 \sqrt{3} }$
= $\frac{3 \sqrt{3} }{3 \sqrt{3} } = 1$

simplificando a $\sqrt{48}$
48:2 = 24:2=12:2=6:2=3:3=1
$\sqrt{ 2^{2} . 2^{2} .3} = 2.2 \sqrt{3} = 4 \sqrt{3}$

simplificando a $\sqrt{192}$
192:2=96:3=32:2=16:2=8:2=4:2=2:2=1
$\sqrt{ 2^{2}. 2^{2}. 2^{2}.3} = 2.2.2 \sqrt{3}=8 \sqrt{3}$

espero ter ajudado... bons estudos!!