Question

7) Faça a transformação de Celsius para Fahrenheit abaixo:
(Use a formula acima: Tc = T1-32)
a) 25C equivale a
b) 30 C equivale a F
c) 12 °C equivale a
F.​

Answer 1

Fórmula:

$\boxed{\sf \large \dfrac{T_{c}}{5} = \dfrac{T_{f} - 32}{9} }$

Letra A

$\sf \dfrac{T_{c}}{5} = \dfrac{T_{f} - 32}{9}$

$\sf \dfrac{25}{5} = \dfrac{T_{f} - 32}{9}$

$\sf 5(T_{f} - 32) = 25\cdot 9$

$\sf 5T_{f} - 160 = 225$

$\sf 5T_{f} = 225 + 160$

$\sf 5T_{f} = 385$

$\sf T_{f} = \dfrac{ 385}{5}$

$\red{\sf T_{f} = 77 \: °C}$

Letra B

$\sf \dfrac{T_{c}}{5} = \dfrac{T_{f} - 32}{9}$

$\sf \dfrac{30}{5} = \dfrac{T_{f} - 32}{9}$

$\sf 5(T_{f} - 32) = 30\cdot 9$

$\sf 5T_{f} - 160 = 270$

$\sf 5T_{f} = 270 + 160$

$\sf 5T_{f} = 430$

$\sf T_{f} = \dfrac{ 430}{5}$

$\red{\sf T_{f} = 86 \: °C}$

Letra C

$\sf \dfrac{T_{c}}{5} = \dfrac{T_{f} - 32}{9}$

$\sf \dfrac{12}{5} = \dfrac{T_{f} - 32}{9}$

$\sf 5(T_{f} - 32) = 12\cdot 9$

$\sf 5T_{f} - 160 = 108$

$\sf 5T_{f} = 108 + 160$

$\sf 5T_{f} = 268$

$\sf T_{f} = \dfrac{ 268}{5}$

$\red{\sf T_{f} = 53,6 \: °C}$