Question

7) Calcular o valor de xe y no triângulo
retângulo da figura abaixo. Me ajuda urgente

Answer 1

Explicação passo-a-passo:

a)

=> Valor de x

$\sf sen~30^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{1}{2}=\dfrac{x}{8}$

$\sf 2x=8\cdot1$

$\sf 2x=8$

$\sf x=\dfrac{8}{2}$

$\sf \red{x=4}$

=> Valor de y

$\sf cos~30^{\circ}=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{y}{8}$

$\sf 2y=8\sqrt{3}$

$\sf y=\dfrac{8\sqrt{3}}{2}$

$\sf \red{y=4\sqrt{3}}$

b)

=> Valor de x

$\sf sen~60^{\circ}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{x}{6}$

$\sf 2x=6\sqrt{3}$

$\sf x=\dfrac{6\sqrt{3}}{2}$

$\sf \red{x=3\sqrt{3}}$

=> Valor de y

$\sf cos~60^{\circ}=\dfrac{cateto~adjacente}{hipotenusa}$

$\sf \dfrac{1}{2}=\dfrac{y}{6}$

$\sf 2y=6\cdot1$

$\sf 2y=6$

$\sf y=\dfrac{6}{2}$

$\sf \red{y=3}$