Question

7- Aplicando a fórmula de Bhaskara, resolva a seguinte equação do segundo grau: x² + 5x + 4 = 0

a) 1 e 4/5
b) 4 e 1
c) -4 e -1
d) 4/5 e 2

Answer 1

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$\sf x^2+5x+4=0\\\sf\Delta=b^2-4ac\\\sf\Delta=5^2-4\cdot1\cdot4\\\sf\Delta=25-16\\\sf\Delta=9\\\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\sf x=\dfrac{-5\pm\sqrt{9}}{2\cdot1}\\\sf x=\dfrac{-5\pm3}{2}\begin{cases}\sf x_1=\dfrac{-5+3}{2}=-\dfrac{2}{2}=-1\checkmark\\\sf x_2=\dfrac{-5-3}{2}=-\dfrac{8}{2}=-4\checkmark\end{cases}\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~c}}}}$