Question

7/6 - [3/2 - (1 - 1/3) + (1 - 3/4)]

Answer 1

$\frac{7}{6}-[ \frac{3}{2} -(1- \frac{1}{3} )+(1- \frac{3}{4} )]= \\ \\ = \frac{7}{6}-[ \frac{3}{2} - (\frac{3-1}{3}) +( \frac{4-3}{4} )]= \\ \\ = \frac{7}{6}-[ \frac{3}{2} - \frac{2}{3} +\frac{1}{4} ]= \\ \\ = \frac{7}{6}-[ \frac{3.6-2.4+1.3}{12} ]= \\ \\ = \frac{7}{6}-[ \frac{18-8+3}{12} ]= \\ \\ = \frac{7}{6}- \frac{13}{12} = \\ \\ = \frac{7.2-13.1}{12} = \frac{14-13}{12} = \frac{1}{12}$

Answer 2

Resposta:

exemplificando 1/12