Question

60\y+2y=26 quem consegue resolver isso?

Answer 1

$\frac{60}{y} + 2y = 26 \\ ( \frac{60}{y} + 2y)y = (26)y \\ 60 + 2y^2 = 26y \\ 60 + 2y^2 - 26y = 0 \\ a = 2, b = -26, c = 60 \\ \\ \Delta = b^2 - 4ac \\ \Delta = (-26)^2 - 4 \times 2 \times 60 \\ \Delta = 676 - 480 \\ \Delta = 196 \\ \\ y = \frac{-b \pm \sqrt{\Delta}}{2a} \\ y = \frac{-(-26) \pm \sqrt{196} }{2 \times 2} \\ y = \frac{26 \pm 14}{4} \\ \\ y' = \frac{26 + 14}{4} = \frac{40}{4} = 10 \\ y'' = \frac{26 - 14}{4} = \frac{12}{4} = 3$

y = 10, y = 3

Answer 2

    60/y + 2y = 26 ----mmc=y
    60 + 2y² - 26y = 0
    2y² - 26y + 60 = 0 (:2)
      y² - 13y + 30 = 0 ----(aplicando Báskara)
      
     Δ= 13² - 4.30 = 169 - 120 = 49
    √Δ= ⁺⁻√49 = ⁺₋7

y1 = (13+7)/2 = 10   
y2 = (13-7)/2 = 3

Resposta:  y = 3  ou  y = 10

Verificando y=3 ------------Verificando y = 10
  60/3 + 2.3 = 26                  60/10 + 2.10 = 26
     20 + 6 = 26                          6  + 20  = 26