Question

-5t²+20t+1,5=0
Qual a resposta ? To perdida gente, alguém ajuda?

Answer 1

Olhar eu usei a fórmula quadrática.
Espero ter te ajudado!

Answer 2

- 5t² + 20t + 1,5 = 0       ×2

- 10t² + 40t + 3 = 0

a = - 10, b = 40, c = 3


Δ = b² - 4 . a . c

Δ = (40)² - 4 . (-10) . 3

Δ = 1600 + 120

Δ = 1720

$x= \dfrac{-b \pm \sqrt{\Delta} }{2a}$

$x= \dfrac{-40 \pm \sqrt{1720} }{-20} \\\\\\x'= \dfrac{-40+ 2\sqrt{430}}{-20} \\\\\\\\x'=2+ \dfrac{ \sqrt{430} }{-10} \\\\\\\\x''=2- \dfrac{ \sqrt{430} }{-10} \\\\\\x''=2+ \dfrac{ \sqrt{430} }{10}$


Forte abraço!