Question

5 x ao quadrado menos 12x + 4 = 0​

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~5x^{2}-12x+4=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=5{;}~b=-12~e~c=4\\\\\Delta=(b)^{2}-4(a)(c)=(-12)^{2}-4(5)(4)=144-(80)=64\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-12)-\sqrt{64}}{2(5)}=\frac{12-8}{10}=\frac{4\div2}{10\div2}=\frac{2}{5}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-12)+\sqrt{64}}{2(5)}=\frac{12+8}{10}=\frac{20}{10}=2\\\\S=\{\frac{2}{5},~2\}$