Question

5^x-2  - 9 = 1 como resolver

 

Answer 1

5^(x - 2) = 1 + 9
5^(x - 2) = 10
log5^(x - 2) = log10
(x - 2)log5 = 1
x - 2 = 1 / log5
x = 2 + 1 / log5
sendo log5 = 0,699:
x = 2 + 1 / 0,699
x = 2 + 1,43061516452
x = 3,43061516452

Answer 2

$5^{x-2}-9=1 \\ \\ 5^{x-2}=10 \\ \\ log5^{x-2}=log10 \\ \\ (x-2)log5=1 \\ \\ x-2=\frac{1}{log5} \\ \\ x=2+\frac{1}{log5} \\ \\ \boxed{x \approx 2,5547}$