Question

5- Um automóvel de massa 200Kg movimenta-se com velocidade de 4m/s. Calcule a sua Energia Cinética.​

Answer 1

Ec= (mv²)/2 —> Ec= (200.4²)/2 —>
Ec= 3 200/2 —> Ec= 1 600

Ec= 1.600 j

Answer 2

$\Large\displaystyle\text{ \begin{gathered} \hookrightarrow\boxed{\boxed{\bf{ E_C= 1600~J }}} \end{gathered} }$

• Explicação:

$\Large\displaystyle\text{ \begin{gathered} \sf{E_C = \dfrac{m \cdot{v} {}^{2} }{2} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{E_C = \dfrac{200 \cdot4 {}^{2} }{2}} \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{E_C = \dfrac{200 \cdot16}{2} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{E_C = \dfrac{3200}{2} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \boxed{\boxed{\sf{E_C =1600 \: J }}} \end{gathered} }$