Question

5- Resolva as equações do2" grau:
a)X2 + X=0
b)x + 5X +6=0​

Answer 1

Resposta:

$A) x^{2} + x = 0$

Δ$= b^{2} - 4ac$

Δ$= 1^{2} - 4 * 1 * 0$

Δ$= 1 - 0$

Δ= 1

x = $\frac{-b ± \sqrt{Δ} }{2a}$

x = $\frac{-1± \sqrt{1} }{2} =$

x1 = $\frac{-1 + 1 }{2} = \frac{0}{2} = 0$

x2 $= \frac{-1 -1}{2} = \frac{-2}{2} = -1$

B) $x^{2} + 5x + 6 = 0$

Δ = $b^{2} - 4ac$

Δ = $5^{2} - 4 * 1 * 6$

Δ = $25 -24$

Δ = 1

$x = \frac{-b +- \sqrt{delta} }{2a}$

$x = \frac{-5 +- \sqrt{1} }{2}$

$x =\frac{ -5 +- 1}{2}$

$x1 = \frac{-5+1}{2} = \frac{-4}{2} = -2$

$x2 = \frac{-5-1}{2} = \frac{-6}{2} = -3$

Explicação passo-a-passo:

espero ter ajudado