Question

5) Qual o volume ocupado por 240 g de CH4 nas CNTP? (C = 12 u e H = 1 u)​

Answer 1

Resposta

1 mol de CH4 _____________ 16 g

x mol de CH4 _____________ 80 g

x = 80 / 16

x = 5,0 mols de CH4

1 mol _____________ 22,4 L nas CNTP

5,0 mols _____________ y L

y = 5,0 . 22,4

y = 112 L