Question

5) Encontre x e y
preciso para agora ​

Answer 1

$sen45=\frac{y}{20\sqrt{2} } \\\\\frac{\sqrt{2} }{2} =\frac{y}{20\sqrt{2} } \\\\20.2=2y\\y=20\\\\x^2+20^2=(20\sqrt{2} )^2\\x^2=800-400=400\\x=\sqrt{400} \\x=20$