Question

(5×+2²)

(×y+3²)

(2ab+4)²

(4×+1)²

(×y+1)²

Answer 1

(5x + 2²) = 5x + 4

(xy + 3²) = xy + 9

(2ab + 4)² = (2ab + 4)(2ab +4) = (2ab)² + 2(2ab)(4) + 4² = 4a²b² + 16ab + 16

(4x + 1)² = (4x + 1)(4x + 1) = (4x)² + 2(4x)(1) + 1² = 16x² + 8x + 1

(xy + 1)² = (xy + 1)(xy + 1) = (xy)² + 2(xy)(1) + 1² = x²y2 + 2xy + 1